RE Tangent lines? ?Find an equation of the line tangent to the following curves at the given point. y= x +3;x = 3

Solution Step 1: 4x Given curve is y= x +3 ;x = 3 We have to find the equation of tangent line to the given curve at given point x=3 The equation of tangent line to the curve y=f(x) at given point (x ,y ) with slope m is given by 0 0 (y y ) = m(x x ) 0 0 Here we have given the point x =0 therefore the corresponding y is 0 0 y = 4(3) = 12 = 12 = 1 0 (3) +3 9+3 12 Therefore the point is (x ,y 0=(301)