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Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James ISBN: 9780198769866 2042

Solution for problem P8B.3 Chapter 8B

Atkins' Physical Chemistry | 11th Edition

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Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James

Atkins' Physical Chemistry | 11th Edition

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Problem P8B.3

The d-metals iron, copper, and manganese form cations with different oxidation states. For this reason, they are found in many oxidoreductases and in several proteins of oxidative phosphorylation and photosynthesis. Explain why many d-metals form cations with different oxidation states.

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Equilibrium Calculations • ex. CO(g) + H2O(g)⁶CO2(g) + H2(g) Kc=0.64 You start with 1.0 mol CO and 1.0 mol CO2 in a 1 L flask. You then add 2.0 mol H2O. What is the concentration of H2 at equilibrium Check for equilibrium first: Q does not equal 0—>system not in equilibrium Make ICE table: CO(g) + H2O(g) ⁶ CO2(g) + H2(g) Initial 1.0 M 2.0 M 1.0 M 0 M Change -x -x +x +x Equilibrium (1.0-x) (2.0-x) (1.0+x) x Kc = 0.64 = [1.0+x][x] [1.0-x][2.0-x] 0.64 = x + x^2 2 - 3x + x^2 0.64(2 - 3x + x^2) = x + x^2 -0.36x^2 - 2.92x + 1.28 = 0 *standard form ax^2 + bx + c = 0 -(-2.92) ± √(-2.92)^2 - 4(-0.36)(1.28) *quadratic formula 2(-0.36) x = -8.5, x = 0.42 *can’t have negative concentration [H2] = 0.42 M

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Chapter 8B, Problem P8B.3 is Solved
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Textbook: Atkins' Physical Chemistry
Edition: 11
Author: Atkins, Peter; De Paula, Julio; Keeler, James
ISBN: 9780198769866

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