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Get Full Access to Atkins' Physical Chemistry - 11 Edition - Chapter 8b - Problem P8b.3
Get Full Access to Atkins' Physical Chemistry - 11 Edition - Chapter 8b - Problem P8b.3

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ISBN: 9780198769866 2042

## Solution for problem P8B.3 Chapter 8B

Atkins' Physical Chemistry | 11th Edition

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Atkins' Physical Chemistry | 11th Edition

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Problem P8B.3

The d-metals iron, copper, and manganese form cations with different oxidation states. For this reason, they are found in many oxidoreductases and in several proteins of oxidative phosphorylation and photosynthesis. Explain why many d-metals form cations with different oxidation states.

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Equilibrium Calculations • ex. CO(g) + H2O(g)⁶CO2(g) + H2(g) Kc=0.64 You start with 1.0 mol CO and 1.0 mol CO2 in a 1 L ﬂask. You then add 2.0 mol H2O. What is the concentration of H2 at equilibrium Check for equilibrium ﬁrst: Q does not equal 0—>system not in equilibrium Make ICE table: CO(g) + H2O(g) ⁶ CO2(g) + H2(g) Initial 1.0 M 2.0 M 1.0 M 0 M Change -x -x +x +x Equilibrium (1.0-x) (2.0-x) (1.0+x) x Kc = 0.64 = [1.0+x][x] [1.0-x][2.0-x] 0.64 = x + x^2 2 - 3x + x^2 0.64(2 - 3x + x^2) = x + x^2 -0.36x^2 - 2.92x + 1.28 = 0 *standard form ax^2 + bx + c = 0 -(-2.92) ± √(-2.92)^2 - 4(-0.36)(1.28) *quadratic formula 2(-0.36) x = -8.5, x = 0.42 *can’t have negative concentration [H2] = 0.42 M

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