?The electron affinity of oxygen is -141 kJ/mol, corresponding to the
Chapter 8, Problem 8.100(choose chapter or problem)
The electron affinity of oxygen is -141 kJ/mol, corresponding to the reaction
\(\mathrm{O}(g)+e^{-} \longrightarrow \mathrm{O}^{-}(g)\)
The lattice energy of K2O(s) is 2238 kJ/mol. Use these data along with data in Appendix C and Figure 7.10 to calculate the “second electron affinity” of oxygen, corresponding to the reaction
\(\mathrm{O}^{-}(g)+e^{-} \longrightarrow \mathrm{O}^{2-}(g)\)
Text Transcription:
O(g)+e^- longrightarrow O^-(g)
O^-(g)+e^- longrightarrow O^2-(g)
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