?Saccharin, a sugar substitute, is a weak acid with \(\mathrm{p} K_{a}=2.32\) at

Chapter 16, Problem 16.61

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Saccharin, a sugar substitute, is a weak acid with \(\mathrm{p} K_{a}=2.32\) at \(25^{\circ} \mathrm{C}\). It ionizes in aqueous solution as follows:

\(\mathrm{HNC}_{7} \mathrm{H}_{4} \mathrm{SO}_{3}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{NC}_{7} \mathrm{H}_{4} \mathrm{SO}_{3}^{-}(a q)\)

What is the pH of a 0.10 M solution of this substance?

Text Transcription:

pKa = 2.32

25^circ C

HNC7H4SO3(aq) rightleftharpoons H+(aq) + NC7H4SO3 -(aq)

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