?The crystalline hydrate \(\mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2} \cdot 4

Chapter 19, Problem 19.86

(choose chapter or problem)

The crystalline hydrate \(\mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2} \cdot 4 \mathrm{H}_{2} \mathrm{O}(s)\) loses water when placed in a large, closed, dry vessel at room temperature:

\(\mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2} \cdot 4 \mathrm{H}_{2} \mathrm{O}(s) \longrightarrow \mathrm{Cd}\left(\mathrm{NO}_{3}\right)_{2}(s)+4 \mathrm{H}_{2} \mathrm{O}(g)\)

This process is spontaneous and \(\Delta H^{\circ}\) is positive at room temperature.

(a) What is the sign of \(\Delta S^{\circ}\) at room temperature?

(b) If the hydrated compound is placed in a large, closed vessel that already contains a large amount of water vapor, does \(\Delta S^{\circ}\) change for this reaction at room temperature?

Text Transcription:

Cd(NO3)2 dot 4H2O(s)

Cd(NO3)2 #4H2O(s) longrightarrow Cd(NO3)2(s) + 4 H2O(g)

Delta H^circ

Delta S^circ