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Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 4 - Problem 65re
Get Full Access to Calculus: Early Transcendentals - 1 Edition - Chapter 4 - Problem 65re

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# Answer: Functions from derivatives Find the function with

ISBN: 9780321570567 2

## Solution for problem 65RE Chapter 4

Calculus: Early Transcendentals | 1st Edition

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Problem 65RE

Find the function with the following properties.

$$h'(x)=sin^2\ x\ and\ h(1)=1\ (Hint: sin^2\ x=(1-\cos\ 2x)/2.)$$

Step-by-Step Solution:

Solution Step 1 In this problem we have to find the original function from its derivative and the initial condition. 2 Given : hx) = sin xand h(1) = 1 We have to find h(x) 2 To find h(x)we need to find the antiderivative(that is., integral) of h(x) = in xand then we use the initial condition h(1) = 1

Step 2 of 2

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