Problem 65RE
Find the function with the following properties.
\(h'(x)=sin^2\ x\ and\ h(1)=1\ (Hint: sin^2\ x=(1-\cos\ 2x)/2.)\)
Step-by-Step Solution:
Solution Step 1 In this problem we have to find the original function from its derivative and the initial condition. 2 Given : hx) = sin xand h(1) = 1 We have to find h(x) 2 To find h(x)we need to find the antiderivative(that is., integral) of h(x) = in xand then we use the initial condition h(1) = 1
Step 2 of 2
