×
Log in to StudySoup
Get Full Access to Atkins' Physical Chemistry - 11 Edition - Chapter 9c - Problem D9c.3
Join StudySoup for FREE
Get Full Access to Atkins' Physical Chemistry - 11 Edition - Chapter 9c - Problem D9c.3

Already have an account? Login here
×
Reset your password

Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James ISBN: 9780198769866 2042

Solution for problem D9C.3 Chapter 9C

Atkins' Physical Chemistry | 11th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James

Atkins' Physical Chemistry | 11th Edition

4 5 1 394 Reviews
15
3
Problem D9C.3

What is the justification for treating s and p atomic orbital contributions to molecular orbitals separately?

Step-by-Step Solution:
Step 1 of 3

Example: which solvent will more likely dissolve the listed species, CHCl 3 (polar) or C6H6(nonpolar) A) C 10 22- C6H6because it is nonpolar B) H 2 – CHCl b3cause it is polar C) HF – CHCl 3ecause it is polar Miscible = able to dissolve completely Fractional Crystallization- the separation of a mixture of substances into pure components on the basis of their differing solubilities Henry’s Law- the solubility of a gas in a liquid in directly proportional to the partial pressure of the gas over the liquid, C = kP. C = concentration (M) of the dissolved gas, P = pressure of gas over the solution, k = constant for each gas-liquid that depends only on the temperature Example: the partial pressure of carbon dioxide in a sealed soda can is approximately 3.8atm and the solubility of carbon dioxide in the soda at this pressure is .13mol/L. Calculate the new solubility of carbon dioxide when the can is opened. The partial pressure of carbon dioxide in the atmosphere is 3.1 x 10 atm. C C 1 C 2 =k = (.13mol/L)/3.8atm = x/3.1x10^-4 atm 3.8x = P P1 P2 4.03 x 10^-5 x = 1.1 x 10^-5 mol/L Concentration Units: 1) Molarity (M) = mol solute/ L solution Disadvantages : 1. Volume varies with temperature 2. Volumes are not always additive 2) Molality (m) = mol solute / mass solvent (kg) Example: calculate the molality of a solution prepared by adding 3.5g of NaCl to 100 mL of water m = mol NaCl / kg H20 1m

Step 2 of 3

Chapter 9C, Problem D9C.3 is Solved
Step 3 of 3

Textbook: Atkins' Physical Chemistry
Edition: 11
Author: Atkins, Peter; De Paula, Julio; Keeler, James
ISBN: 9780198769866

Other solutions

Discover and learn what students are asking



Calculus: Early Transcendental Functions : Conservative Vector Fields and Independence of Path
?In Exercises 1 - 4, show that the value of \(\int_{C} F \cdot d r\) is the same for each parametric representation of C. \(\mathbf{F}(x, y)=y








Statistics: Informed Decisions Using Data : Inference about the Difference between Two Medians: Dependent Samples
?In Problems 3–10, use the Wilcoxon matched-pairs signedranks test to test the given hypotheses at the a = 0.05 level of significance. The dependent sa


People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to: