?Consider the molecule \(\mathrm{F}_{2} \mathrm{C}=\mathrm{CF}_{2}\) (point group \(D_{2

Chapter 10, Problem P10C.8

(choose chapter or problem)

Consider the molecule \(\mathrm{F}_{2} \mathrm{C}=\mathrm{CF}_{2}\) (point group \(D_{2 \mathrm{~h}}\)), and take it as lying in the xy-plane, with x directed along the C–C bond. (a) Consider a basis formed from the four \(2 \mathrm{p}_{z}\) orbitals from the fluorine atoms: show that the basis spans \(\mathrm{B}_{1 \mathrm{u}}\), \(\mathrm{B}_{2 \mathrm{g}}\), \(\mathrm{B}_{3 \mathrm{g}}\), and \(A_{u}\). (b) By applying the projection formula to one of the \(2 \mathrm{p}_{z}\)) orbitals, generate the SALCs with the indicated symmetries. (c) Repeat the process for a basis formed from four \(2 p_{x}\) orbitals (the symmetry species will be different from those for \(2 \mathrm{p}_{z}\)).

Text Transcription:

F_2C=CF_2

D_2h

2p_z

B_1u

B_2g

A_u

2p_x

2p_z