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Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James ISBN: 9780198769866 2042

Solution for problem P11B.3 Chapter 11B

Atkins' Physical Chemistry | 11th Edition

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Atkins' Physical Chemistry | 11th Edition | ISBN: 9780198769866 | Authors: Atkins, Peter; De Paula, Julio; Keeler, James

Atkins' Physical Chemistry | 11th Edition

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Problem P11B.3

The rotational constant of \(\mathrm{NH}_{3}\) is 298GHz. Calculate the separation of the pure rotational spectrum lines as a frequency (in GHz) and a wavenumber (in \(\mathrm{cm}^{-1}\)), and show that the value of B is consistent with an N–H bond length of 101.4pm and a bond angle of \(106.78^{\circ}\).

Text Transcription:

NH_3

cm^-1

106.78^circ

Step-by-Step Solution:
Step 1 of 3

Pericyclic Reactions Predicting the product when both reagents are unsymmetrically substituted D ­ Donating group W ­ Withdrawing group Formation of 1,4 ­ Product Example: Formation of 1,2 ­ Product Example: The formation of ​ 1,3 ­ Product​ will not form. If a Diels–​Alder reaction creates a product with a chiral center, than it will product a racemic mixture. Retrosynthetic Analysis of the Diels Alder Reaction MO Description of Cycloadditions If there is a conversation of orbital symmetry, then it is symmetry­allowed​ . When the orbital doesn’t overlap, it is ​symmetry­forbidden.​ This is a [2+2] cycloaddition. Here, an electron in the HOMO will move to LUMO in the other. When [2+2] cycloaddition is react with ​ heat, the orbital will create symmetry­forbidden, so​ light is the only way a [2+2] cycloaddition can react. Electrocyclic Reactions Thermal Photochemical (light) Four π electrons Conrotatory

Step 2 of 3

Chapter 11B, Problem P11B.3 is Solved
Step 3 of 3

Textbook: Atkins' Physical Chemistry
Edition: 11
Author: Atkins, Peter; De Paula, Julio; Keeler, James
ISBN: 9780198769866

Atkins' Physical Chemistry was written by Aimee Notetaker and is associated to the ISBN: 9780198769866. The full step-by-step solution to problem: P11B.3 from chapter: 11B was answered by Aimee Notetaker, our top Chemistry solution expert on 04/25/22, 03:45PM. This full solution covers the following key subjects: . This expansive textbook survival guide covers 327 chapters, and 1120 solutions. This textbook survival guide was created for the textbook: Atkins' Physical Chemistry, edition: 11. The answer to “?The rotational constant of \(\mathrm{NH}_{3}\) is 298GHz. Calculate the separation of the pure rotational spectrum lines as a frequency (in GHz) and a wavenumber (in \(\mathrm{cm}^{-1}\)), and show that the value of B is consistent with an N–H bond length of 101.4pm and a bond angle of \(106.78^{\circ}\).Text Transcription:NH_3cm^-1106.78^circ” is broken down into a number of easy to follow steps, and 49 words. Since the solution to P11B.3 from 11B chapter was answered, more than 201 students have viewed the full step-by-step answer.

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