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Get Full Access to Introduction To Chemical Engineering Thermodynamics - 8 Edition - Chapter 13 - Problem 13.18
Get Full Access to Introduction To Chemical Engineering Thermodynamics - 8 Edition - Chapter 13 - Problem 13.18

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ISBN: 9781259696527 2049

## Solution for problem 13.18 Chapter 13

Introduction to Chemical Engineering Thermodynamics | 8th Edition

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Introduction to Chemical Engineering Thermodynamics | 8th Edition

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Problem 13.18

A liquid mixture of cyclohexanone(1)/phenol(2) for which $$x_{1}=0.6$$ is in equilibrium with its vapor at $$144^{\circ} \mathrm{C}$$. Determine the equilibrium pressure P and vapor composition $$y_{1}$$ from the following information:

$$\ln \gamma_{1}=A x_{2}^{2} \quad \ln \gamma_{2}=A x_{1}^{2}$$

$$\text { At } 144^{\circ} \mathrm{C}, P_{1}^{\text {sat }}=75.20 \mathrm{kPa} \text { and } P_{2}^{\text {sat }}=31.66 \mathrm{kPa}$$

The system forms an azeotrope at $$144^{\circ} \mathrm{C}$$ for which $$x_{1}^{\mathrm{az}}=y_{1}^{\mathrm{az}}=0.294$$

Text Transcription:

x_1=0.6

144^circ C

y_1

ln gamma_1=A x_2^2 ln gamma_2=Ax_1^2

At 144^circ C, P_1^sat=75.20kPa and P_2^sat=31.66kPa

x_1^az=y_1^az=0.294

Step-by-Step Solution:
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##### ISBN: 9781259696527

Introduction to Chemical Engineering Thermodynamics was written by Aimee Notetaker and is associated to the ISBN: 9781259696527. The full step-by-step solution to problem: 13.18 from chapter: 13 was answered by Aimee Notetaker, our top Engineering and Tech solution expert on 06/03/22, 04:28PM. The answer to “?A liquid mixture of cyclohexanone(1)/phenol(2) for which $$x_{1}=0.6$$ is in equilibrium with its vapor at $$144^{\circ} \mathrm{C}$$. Determine the equilibrium pressure P and vapor composition $$y_{1}$$ from the following information:? $$\ln \gamma_{1}=A x_{2}^{2} \quad \ln \gamma_{2}=A x_{1}^{2}$$? $$\text { At } 144^{\circ} \mathrm{C}, P_{1}^{\text {sat }}=75.20 \mathrm{kPa} \text { and } P_{2}^{\text {sat }}=31.66 \mathrm{kPa}$$? The system forms an azeotrope at $$144^{\circ} \mathrm{C}$$ for which $$x_{1}^{\mathrm{az}}=y_{1}^{\mathrm{az}}=0.294$$Text Transcription:x_1=0.6144^circ Cy_1ln gamma_1=A x_2^2 ln gamma_2=Ax_1^2At 144^circ C, P_1^sat=75.20kPa and P_2^sat=31.66kPax_1^az=y_1^az=0.294” is broken down into a number of easy to follow steps, and 77 words. This full solution covers the following key subjects: . This expansive textbook survival guide covers 15 chapters, and 96 solutions. Since the solution to 13.18 from 13 chapter was answered, more than 200 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introduction to Chemical Engineering Thermodynamics, edition: 8.

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