?The solubility of AgCl(s) in water at \(25^{\circ} \mathrm{C}\) is \(1.33 \times
Chapter 19, Problem 102(choose chapter or problem)
The solubility of AgCl(s) in water at \(25^{\circ} \mathrm{C}\) is \(1.33 \times 10^{-5} \mathrm{~mol} / \mathrm{L}\) and its \(\Delta H^{\circ}\) of solution is 65.7 kJ/mol. What is its solubility at \(50.0^{\circ} \mathrm{C}\)?
Text Transcription:
25^circ C
1.33 x 10-5 mol/L
Delta H^circ
50.0^circ C
Unfortunately, we don't have that question answered yet. But you can get it answered in just 5 hours by Logging in or Becoming a subscriber.
Becoming a subscriber
Or look for another answer