?When hydrazine is dissolved in water, it acts like a base.\(\mathrm{N}_{2}

Chapter 24, Problem 95

(choose chapter or problem)

When hydrazine is dissolved in water, it acts like a base.

\(\mathrm{N}_{2} \mathrm{H}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{N}_{2} \mathrm{H}_{5}^{+}(a q)+\mathrm{OH}^{-}(a q) \\ K_{\mathrm{b}_{1}}=8.5 \times 10^{-7}\)

\(\mathrm{N}_{2} \mathrm{H}_{5}^{+}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \rightleftharpoons \mathrm{N}_{2} \mathrm{H}_{6}^{2+}(a q)+\mathrm{OH}^{-}(a q) \\ K_{\mathrm{b}_{2}}=8.9 \times 10^{-16}\)

a. Calculate the \(K_{\mathrm{b}}\) for the overall reaction of hydrazine forming \(\mathrm{N}_{2} \mathrm{H}_{6}{ }^{2+}\).

b. Calculate \(K_{\mathrm{a}_{1}}\) for \(\mathrm{N}_{2} \mathrm{H}_{5}{ }^{+}\).

c. Calculate the concentration of hydrazine and both cations in a solution buffered at a pH of 8.5 for a solution that was made by dissolving 0.012 mol of hydrazine in 1 L of water.

Text Transcription:

N_2H_4(aq) + H_2O(l) rightleftharpoons  N_2H_5 +(aq) + OH-(aq) Kb_1 = 8.5 x 10-7

N_2H_5 +(aq) + H_2O(l) rightleftharpoons N_2H_6 2+(aq) + OH-(aq) Kb_2 = 8.9 * 10-16

K_b

N_2H_6 2+

K_a1

N_2H_5 +.