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Maximum area rectangles Of all rectangles with a perimeter

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 5E Chapter 4.4

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 5E

Maximum area rectangles Of all rectangles with a perimeter of 10 m, which one has the maximum area? (Give the dimensions.)

Step-by-Step Solution:

Solution Step 1: Consider a rectangle of width x and length y here area of rectangle(length *width) is the objective function denote it by A Thus the objective function A=xy And perimeter of a rectangle is the constraints that is 2(x+y)=10m Our goal is to find the dimension of a rectangle of a perimeter 10m which gives maximum area Step 2: The first step is to use the constraints 2(x+y)=10 to express the objective function.A=xy in terms of a single variable For this 2(x+y)=10 (x+y)=5 (x+y)=5 The first step is to use the constraint to express the objective function A in terms of a single variable either in x or y suppose we express the objective function in terms of x For this; Step 3: Substitute for y the objective function A becomes A=xy =x(5-x) 2 A=5x-x 0 x 5 Which is the function of single variable with A(0)=A(5)=0

Step 4 of 6

Chapter 4.4, Problem 5E is Solved
Step 5 of 6

Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

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Maximum area rectangles Of all rectangles with a perimeter

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