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Rectangles beneath a semi circle A rectangle is

Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett ISBN: 9780321570567 2

Solution for problem 19E Chapter 4.4

Calculus: Early Transcendentals | 1st Edition

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Calculus: Early Transcendentals | 1st Edition | ISBN: 9780321570567 | Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

Calculus: Early Transcendentals | 1st Edition

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Problem 19E

Rectangles beneath a semi circle A rectangle is constructed with its base on the diameter of a semicircle with radius 5 cm and with two vertices on the semicircle. What are the dimensions of the rectangle with maximum area?

Step-by-Step Solution:

Solution Step 1: The equation of semicircle with radius 5 is 2 2 2 x + y = 5 x + y = 25 So y= 25 x 2 Let the length of rectangle be 2x And breadth of the rectangle be y Then area of the rectangle is given by A=2xy Step 2 2 The requirement of the rectangle lies on on the semicircle of y= 25 x That is A=2x( 25 x )2 ;0 x 5 The variable x is restricted between [0,5] at which both points yield a minimum value of 0 area

Step 3 of 4

Chapter 4.4, Problem 19E is Solved
Step 4 of 4

Textbook: Calculus: Early Transcendentals
Edition: 1
Author: William L. Briggs, Lyle Cochran, Bernard Gillett
ISBN: 9780321570567

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Rectangles beneath a semi circle A rectangle is

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