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Solution: The thermal decomposition of phosphine (PH3) into

Chapter 13, Problem 12.26

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QUESTION:

The thermal decomposition of phosphine \(PH_3)\ into phosphorus and molecular hydrogen is a first-order reaction:

\4PH_3(g) + P_4(g) \rightarrow  6H_2(g)\

The half-life of the reaction is 35.0 s at \680^oC\. Calculate

(a) the first-order rate constant for the reaction and (b) the time required for 95 percent of the phosphine to decompose.

Questions & Answers

QUESTION:

The thermal decomposition of phosphine \(PH_3)\ into phosphorus and molecular hydrogen is a first-order reaction:

\4PH_3(g) + P_4(g) \rightarrow  6H_2(g)\

The half-life of the reaction is 35.0 s at \680^oC\. Calculate

(a) the first-order rate constant for the reaction and (b) the time required for 95 percent of the phosphine to decompose.

ANSWER:

Step 1 of 3

(a)

The given chemical reaction is as follows;

                                                $$ 4PH_3 (g) \rightarrow P_4(g) + 6H_2(g)$$

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