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Get Full Access to Chemistry: The Central Science - 12 Edition - Chapter 10 - Problem 53e
Get Full Access to Chemistry: The Central Science - 12 Edition - Chapter 10 - Problem 53e

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# Further Applications of the Ideal-Gas Equation | Ch 10 - 53E

ISBN: 9780321696724 27

## Solution for problem 53E Chapter 10

Chemistry: The Central Science | 12th Edition

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Problem 53E

Problem 53E

Further Applications of the Ideal-Gas Equation (Section)

(a) Calculate the density of NO2 gas at 0.970 atm and 35 °C. (b) Calculate the molar mass of a gas if 2.50 g occupies 0.875 L at 685 torr and 35 °C.

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Elements of Statistics – Chapter 6 Notes Key Points  Density Curves  Normal Distribution  Standard Normal Curve  Standard Normal Table Density Curve  A fitted curve in regard to distribution  Is ALWAYS ON or ABOVE the horizontal axis  Total area under a density curve is always equal to 1 o Density Histogram To determine the density of a class, take the relative frequency and divide by the width of class. AREA = DENSITY x WIDTH Normal Distribution  A variable is “normally distributed” if its distribution has the shape of a symmetric curve. o Characterized by its Mean, , and a Standard Deviation, o The Mean

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##### ISBN: 9780321696724

Since the solution to 53E from 10 chapter was answered, more than 390 students have viewed the full step-by-step answer. Chemistry: The Central Science was written by and is associated to the ISBN: 9780321696724. This full solution covers the following key subjects: gas, calculate, applications, Density, equation. This expansive textbook survival guide covers 49 chapters, and 5471 solutions. This textbook survival guide was created for the textbook: Chemistry: The Central Science, edition: 12. The full step-by-step solution to problem: 53E from chapter: 10 was answered by , our top Chemistry solution expert on 04/03/17, 07:58AM. The answer to “Further Applications of the Ideal-Gas Equation (Section)(a) Calculate the density of NO2 gas at 0.970 atm and 35 °C. (b) Calculate the molar mass of a gas if 2.50 g occupies 0.875 L at 685 torr and 35 °C.” is broken down into a number of easy to follow steps, and 39 words.

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