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Get Full Access to Chemistry: The Central Science - 12 Edition - Chapter 10 - Problem 59e
Get Full Access to Chemistry: The Central Science - 12 Edition - Chapter 10 - Problem 59e

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# Further Applications of the Ideal-Gas Equation | Ch 10 - 59E ISBN: 9780321696724 27

## Solution for problem 59E Chapter 10

Chemistry: The Central Science | 12th Edition

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Problem 59E

Problem 59E

Further Applications of the Ideal-Gas Equation (Section)

The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas:

C6H12O6(aq) + 6 O2(g)→6 CO2(g) + 6 H2O(l)

(a) Calculate the volume of dry CO2 produced at body temperature (37 °C) and 0.970 atm when 24.5 g of glucose is consumed in this reaction. (b) Calculate the volume of oxygen you would need, at 1.00 atm and 298 K, to completely oxidize 50.0 g of glucose.

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Chem 1010 9/6 – 9/8/2017 Class Notes Area  The area of a plane rectangle = length x width  Area of plane triangle = height x base / 2  Area enclosed by a plane circle = pi x radius 2(squared)  Three Dimensional objects have a surface area Volume, V In three dimensions we are more interests in volume. Volume is a measure of how much stuff you’ve got, a quantity of matter Liter is commonly used for fluids Liter was originally a base unit in the metric system Density Density is defined as mass / volume; d = m / V Water: 1.00 g per mL (1.00g/mL) –NEED TO KNOW- Temperature The volume increases as the temperature increases Celsius 100 C degrees=180 F degrees, 5 C=9 F degrees To Convert to F to C: calculate how many F degrees away from 32F Add or subtract 32 Compounds and Elements -original substance is a compound -if you can’t decompose into 2 by chemical process into 2 or more substances Quicklime from Limestone Lime stone: common gray sedimentary rock -very common -formed from marine organisms Quicklime: is made from roasting limestone -used for making mortar 280 Mt(megaton)(1 t = 100kg Limestone decomposes to quicklime Carbon Dioxide Joseph Black Antoine Lavoisier Combination reaction: Carbon + oxygen  carbon dioxide (-)Burning (reaction with oxygen) = combustion Law of conversation of mass Based on observation, have to of done experiments which then leads us to a conclusion Composition of Compounds Zinc + Oxygen = Zinc Oxide Zinc increases - oxygen increases- quantity zinc oxide increases Law of Multiple Prop

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