You toss a ball straight up with an initial speed of 30 m/s. How high does it go, and how long is it in the air (neglecting air resistance)?

Solution 1P Step 1 : A ball is tossed in air with initial velocity of 30 m/s , we need to find the maximum height reached by the ball in air , we are ignoring the air resistance Considering the data given Velocity with which ball is tossed v = 3i m/s Step 2 : Let us first calculate the time taken by the ball to reach maximum height Since the ball is thrown up in the air it will have to go against the gravitational force of the earth Gravitational force is given by g = 9.8 m/s 2 Time taken is given by t = vi÷ g Substituting the values we get t = 30 m/s ÷ 9.8 m/s 2 t = 3.061 s Hence the ball takes 3.06 s to reach maximum height