A Fast Pitch.? The fastest measured pitched baseball left the pitcher’s hand at a speed of 45.0 m/s. If the pitcher was in contact with the ball over a distance of 1.50 m and produced constant acceleration, (a) what acceleration did he give the ball, and (b) how much time did it take him to pitch it?

Solution 21E Step 1 : Let us consider the data given Initial velocity of the baseball v = 0 m/s i Final velocity of the baseball v = 45.0 m/s f Distance travelled by pitcher with ball d = 1.50 m Step 2 : To find the acceleration of the ball We have relation for acceleration as 2ad = v v2 2 f i Here a=acceleration vf final velocity v initial velocity i d= distance travelled Rearrange to find acceleration We get v v 2 a = f i 2d Substituting the values we get 2 2 a = (45 m/s) 0 2×1.5 m a = 2025 m /s 3.0m 2 a = 675 m/s Hence the acceleration transferred to baseball is 675 m/s 2