Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. (a) It the faster stone takes 10 s to return to the ground, how long will it take the slower stone to return? (b) If the slower stone reaches a maximum height of ?H?, how high (in terms of ?H?) will the faster stone go? Assume free fall.
Solution 49E Step 1 : Let us consider stones as A and B and speed as x So we have Speed of Stone A =x Speed of Stone B =3x Final time for stone B t = 10 s f Height reached by stone A = H