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Can the total work done on an object during a displacement

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 12DQ Chapter 6

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 12DQ

Can the ?total? work done on an object during a displacement be negative? Explain. If the total work is negative, can its magnitude be larger than the initial kinetic energy of the object? Explain.

Step-by-Step Solution:

Solution 12DQ Step 1: According to the equation for work done, W = F.S = FS cos Where, F - Force applied S - Displacement for the object - Angle between the direction of force and the direction of displacement If both are in same direction, then = 0 and = FS But, if the force applied and motion are in opposite direction, then, = 180 Therefore, W = - FS So, the total work done can be negative according to the direction of force and displacement.

Step 2 of 2

Chapter 6, Problem 12DQ is Solved
Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

The answer to “Can the ?total? work done on an object during a displacement be negative? Explain. If the total work is negative, can its magnitude be larger than the initial kinetic energy of the object? Explain.” is broken down into a number of easy to follow steps, and 34 words. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: work, Object, Negative, explain, its. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 12DQ from chapter: 6 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. Since the solution to 12DQ from 6 chapter was answered, more than 697 students have viewed the full step-by-step answer.

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