Can the ?total? work done on an object during a displacement be negative? Explain. If the total work is negative, can its magnitude be larger than the initial kinetic energy of the object? Explain.

Solution 12DQ Step 1: According to the equation for work done, W = F.S = FS cos Where, F - Force applied S - Displacement for the object - Angle between the direction of force and the direction of displacement If both are in same direction, then = 0 and = FS But, if the force applied and motion are in opposite direction, then, = 180 Therefore, W = - FS So, the total work done can be negative according to the direction of force and displacement.