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Calculate the emf of the following concentration cell:

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 18.36 Chapter 18

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 18.36

Calculate the emf of the following concentration cell: Mg(s) 0 Mg21(0.24 M) 0 0 Mg21(0.53 M) 0 Mg(s)

Step-by-Step Solution:
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­every cell has a living outer boundary • cell membrane • eukaryotic the nucleus is the difference between a prokaryote and a eukaryote ­cytoplasm, ­cyto =cell the liquid between the nucleus and the outer membrane pro=before the nucleus eukaryotes have some kind of membrane bound organelle 1)prokaryotic: without nucleus 2. Eukaryotic: with nucleus Cell growth 1. increase in size— surface area increases at slower rate than volume (S.A/ Vol.) **** cell is 60­90% water, there has to be enough surface area to support the volume. once the cell gets to big it either dies or it has to divide to support the volume. Volume goes up faster than surface area. The denominator goes up faster than the numinator**** 2. Division 1. duplication ­ replication DNA 2. separation **chromosomes are vehicles of DNA Prokaryotic Cells ** ——> prokaryotic cells Binary Fission (cell reproduction process) 1. duplication (replication) of circular DNA 2. fissure in cell membrane, grows inward 3. DNA strands pulled apart via attachment to cell membrane 4. fissure splits into two daughter cells *fission occurs when there is not enough surface area for volume** Eukaryotic Cells> Mi

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Chapter 18, Problem 18.36 is Solved
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Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

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Calculate the emf of the following concentration cell: