A block of ice with mass 2.00 kg slides 0.750 m down an inclined planethat slopes downward at an angle of 36.9° below the horizontal. If the block of ice stalls from rest, what is its final speed? You can ignore friction.

Solution 28E Step 1: Let us consider the graphical representation of question Data given Mass m = 2.0 kg Distance x = 0.75 m = 36.9 0 Step 2 : Let us find the height of the inclined plane It is obtained as y = 0.75 sin (36.9) y = 0.450 m Hence we have height as 0.450 m Step 3 : We shall the energy used to slide along the inclined plane It is given b y U = mgh Here h = y = 0.450 m 2 g = 9.8 m/ s m = 2 kg Substituting the values we get 2 U = 2.0 kg × 9.8 m/s × 0.450 m U = 8.82 J Hence we have energy used as 8.82 J