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Solved: A silver rod and a SHE are dipped into a saturated

Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro ISBN: 9780321809247 1

Solution for problem 18.105 Chapter 18

Chemistry: A Molecular Approach | 3rd Edition

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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro

Chemistry: A Molecular Approach | 3rd Edition

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Problem 18.105

A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25C. The measured potential difference between the rod and the SHE is 0.589 V, the rod being positive. Calculate the solubility product constant for silver oxalate

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Introduction to Chapter 1:  Difference of Squares: a -b =(a-b)(a+b)  Zero Product Property: ab=0; a, b=0 1.1 Linear Equations are first-degree equations in one variable that contain the equality symbol, “=”. Linear equation in the variable x can be expresses in the standard form, ax+b=c, where a ≠, b ∊ ℝ The domain is the largest set of acceptable input values. Of note, the denominator of a fraction cannot be equal to zero. 1.1.1 Solve ax+b=0, solve for x ax+(b-b)=(0-b) 1. Isolate x by subtracting b from both sides. x/a=-b/a 2. Divide both sides by a x=-b/a 1.1.2 Solve 5x-3=2x+8 -2x -2x 1. Subtract 2x from each side 3x-3=8 +3 +3 2. Add 3 to each side 3x=11 /3 /3 3. Divide each side by 3 x=11/3 1.1.3 Solve 400t-85=11-50t +50t +50t 1. Add 50t to each side 450t-85=11 +85 +85 2. Add 85 to each side 450t=96 /450 /450 3. Divide each side by 450 t=16/75 1.1.4 Solve 11-4(5+3x)+2(6x-7)=0 for x 11-4(5+3x)+2(6x-7)=0 11-20+12x+12x-14=0 1. Use distributive property 24x-23=0 2. Combine like terms x=-23/24 3. Simplify 1.1.5 2 Solve S=2πr +2πrh for h 2 2 S=2πrh +2πrh (S-2πrh )/(2πr)=h 1.1.6 x− = 5 6 2 24 x 1 5 24( 6 =2 24) 1. Multiply all by LCD

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Chapter 18, Problem 18.105 is Solved
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Textbook: Chemistry: A Molecular Approach
Edition: 3
Author: Nivaldo J. Tro
ISBN: 9780321809247

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Solved: A silver rod and a SHE are dipped into a saturated