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Get Full Access to University Physics - 13 Edition - Chapter 6 - Problem 52e
Get Full Access to University Physics - 13 Edition - Chapter 6 - Problem 52e

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# A 20.0-kg rock is sliding on a rough, horizontal surface ISBN: 9780321675460 31

## Solution for problem 52E Chapter 6

University Physics | 13th Edition

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Problem 52E

A 20.0-kg rock is sliding on a rough, horizontal surface at 8.00 m/s and eventually stops due to friction. The coefficient of kinetic friction between the rock and the surface is 0.200. What average power is produced by friction as the rock stops?

Step-by-Step Solution:

Solution 52E Step 1: Consider the data given Mass of rock m = 20 kg Velocity of the down the inclined plane v = 8 m/s Kinetic friction M K = 0.200 Let us find the kinetic energy of the rock This is obtained by using KE = (1/2) mv 2 Substituting the values we get 2 KE = (1/2) × 20 kg × (8.0 m/s) KE = 640 J Thus we find kinetic energy as 640 J

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##### ISBN: 9780321675460

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