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A thin, light string is wrapped around the outer rim of a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 27E Chapter 10

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 27E

A thin, light string is wrapped around the outer rim of a uniform hollow cylinder of mass 4.75 kg having inner and outer radii as shown in ?Fig. E10.25?. The cylinder is then released from rest. (a) How far must the cylinder fall before its center is moving at 6.66 m/s? (b) If you just dropped this cylinder without any string, how fast would its center be moving when it had fallen the distance in part (a)? (c) Why do you get two different answers when the cylinder falls the same distance in both cases?

Step-by-Step Solution:

Solution 27E Step 1: Initially, the kinetic energy of the system was zero since, the cylinder was at rest. Then, the energy will be completely potential and it will be, PE initialmgH The kinetic energy of the system can be calculated when the speed is 6.66 m/s. The kinetic energy at a speed v can be given by, KE = KE translational Rotational 2 KE translational½ mv Where, m is th mass of the system. 2 KE rotational½ I Where, I - moment of inertia of the system and - Angular velocity

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Chapter 10, Problem 27E is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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A thin, light string is wrapped around the outer rim of a