An electric motor consumes 9.00 kJ of electrical energy in 1.00 min. If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor output, how much torque will this engine develop if you run it at 2500 rpm?

Solution 32E Step 1 of 4: Given electric motor runs with angular speed of = 2500 rev/minby consuming the electrical energy E=9kJ in t= 1min. In total consumed energy(E) , 2E is going to motor 3 1 output and 2E energy goes as heat and other forms. We need to calculate the torque developed during this process. Step 2 of 4: Given data, Total energy, E= 9 kJ Using 1kJ= 10 J3 E=9× 10 J 3 1 2 Motor uses, E = E 3 3 1 2 3 Using E=9× 10 J E = (93× 10 J) E = 6 × 10 J3 Time taken , t= 1min Using 1 min= 60 s t = 60 s Angular speed, = 2500 rev/min Using 1 rev =2 rad and 1 min = 60 s = 2500 ×2rev/min 60 = 261.67 rad/s