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Stabilization of the Hubble Space Telescope. The Hubble

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 56E Chapter 10

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 56E

Stabilization of the Hubble Space Telescope.? The Hubble Space Telescope is stabilized to within an angle of about 2-millionths of a degree by means of a series of gyroscopes that spin at 19,200 rpm. Although the structure of these gyroscopes is actually quite complex, we can model each of the gyroscopes as a thin-walled cylinder of mass 2.0 kg and diameter 5.0 cm, spinning about its central axis. How large a torque would it take to cause these gyroscopes to precess through an angle of 1.0 X 10-6 degree during a 5.0-hour exposure of a galaxy?

Step-by-Step Solution:

Solution 56E Introduction From the given angular displacement and time we can calculate the angular speed of precession. Then using the formula of angular speed of precession we can calculate the required torque. Step 1 The angular displacement is = 1.0 × 10 ° = 1.745 × 1rad The time is t = 5.0 hr = 18000 s Hence the angular speed of precession is

Step 2 of 4

Chapter 10, Problem 56E is Solved
Step 3 of 4

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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Stabilization of the Hubble Space Telescope. The Hubble