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The mechanism shown in Fig. P10.60 is used to raise a

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 68P Chapter 10

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 68P

The mechanism shown in ?Fig. P10.60? is used to raise a crate of supplies from a ship’s hold. The crate has total mass 50 kg. A rope is wrapped around a wooden cylinder that turns on a metal axle. The cylinder has radius 0.25 m and moment of inertia about the axle. The crate is suspended from the free end of the rope. One end of the axle pivots on frictionless bearings; a crank handle is attached to the other end. When the crank is turned, the end of the handle rotates about the axle in a vertical circle of radius 0.12 m, the cylinder turns, and the crate is raised. What magnitude of the force applied tangentially to the rotating crank is required to raise the crate with an acceleration of 1.40 m/s2? (You can ignore the mass of the rope as well as the moments of inertia of the axle and the crank.)

Step-by-Step Solution:
Step 1 of 3

Solution 68P This question involves two torque terms. One is related to raise the crate and the other is to turn the cylinder. Let us now calculate each torque. Given, mass of the crate M = 5c kg Since, the crate moves up with an acceleration of 1.40 m/s , hence total force required to move the crate upward is F = 50 kg × (9.80 + 1.40) m/s = 560 N 1 Torque associated with this force is = F × 0.25 m ( radius of cylinder =0.25 m) 1 1 1 = 560 N × 0.25 m = 140 N.m Torque required to turn the cylinder is 2 = Moment of inertia × angular acceleration 2 = 2.9 kg.m ×2 1.40rad/s 2 0.25 = 16.24 N.m 2 Therefore, net torque involved in the process = + 1 2 = 140 N.m + 16.24 N.m = 156.24 N.m Radius of the vertical circle = 0.12 m Now, = F × 0.12 m F = 156.24 N.m/0.12 m = 1302 N Therefore, the approximate magnitude of the force is 1302 N .

Step 2 of 3

Chapter 10, Problem 68P is Solved
Step 3 of 3

Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

The answer to “The mechanism shown in ?Fig. P10.60? is used to raise a crate of supplies from a ship’s hold. The crate has total mass 50 kg. A rope is wrapped around a wooden cylinder that turns on a metal axle. The cylinder has radius 0.25 m and moment of inertia about the axle. The crate is suspended from the free end of the rope. One end of the axle pivots on frictionless bearings; a crank handle is attached to the other end. When the crank is turned, the end of the handle rotates about the axle in a vertical circle of radius 0.12 m, the cylinder turns, and the crate is raised. What magnitude of the force applied tangentially to the rotating crank is required to raise the crate with an acceleration of 1.40 m/s2? (You can ignore the mass of the rope as well as the moments of inertia of the axle and the crank.)” is broken down into a number of easy to follow steps, and 155 words. Since the solution to 68P from 10 chapter was answered, more than 478 students have viewed the full step-by-step answer. University Physics was written by and is associated to the ISBN: 9780321675460. This textbook survival guide was created for the textbook: University Physics, edition: 13. This full solution covers the following key subjects: axle, crate, end, crank, rope. This expansive textbook survival guide covers 26 chapters, and 2929 solutions. The full step-by-step solution to problem: 68P from chapter: 10 was answered by , our top Physics solution expert on 05/06/17, 06:07PM.

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