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A 5.00-kg ball is dropped from a height of 12.0 m above

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman ISBN: 9780321675460 31

Solution for problem 88P Chapter 10

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 88P

A 5.00-kg ball is dropped from a height of 12.0 m above one end of a uniform bar that pivots at its center. The bar has mass 8.00 kg and is 4.00 m in length. At the other end of the bar sits another 5.00-kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision. How high will the other ball go after the collision?

Step-by-Step Solution:

Solution 88P Step 1 : Data given Mass of the ball M b = 5 kg Distance before collision h = 12.0 m Mass of the bar M bar = 8 kg Length of the bar L = 4.0 m We need to find the distance travelled by the ball at the other end of the bar when a ball is collided with bar at front end We shall find the potential energy of the ball It is given by U = 2gh Substituting values we get U = 2 × 9.8 m/s × 12.0 m U = 235.2 J U = 15.3J Hence the potential energy of the ball is 15.3 J Step 2 : We shall angular velocity of the ball as it collides with the bar It is given by Consider L1= L 2y law of conservation L1 length of the bar before collision L2 length of the bar after collision Hence we can write this as M UR = I b M bar2 2 M Ub = ( 12 + 2M RB) Substituting values we get 8 kg×(4.0 m ) 2 5 kg × 15.3 J × 2m = ( 12 + 2 × 5kg × 2 ) 153 kg m = (50.6 kg m ) 2 = 153 kg m /50.6 kg m 2 = 3.023 rad /s

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Chapter 10, Problem 88P is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

University Physics was written by and is associated to the ISBN: 9780321675460. The full step-by-step solution to problem: 88P from chapter: 10 was answered by , our top Physics solution expert on 05/06/17, 06:07PM. The answer to “A 5.00-kg ball is dropped from a height of 12.0 m above one end of a uniform bar that pivots at its center. The bar has mass 8.00 kg and is 4.00 m in length. At the other end of the bar sits another 5.00-kg ball, unattached to the bar. The dropped ball sticks to the bar after the collision. How high will the other ball go after the collision?” is broken down into a number of easy to follow steps, and 70 words. This textbook survival guide was created for the textbook: University Physics, edition: 13. Since the solution to 88P from 10 chapter was answered, more than 495 students have viewed the full step-by-step answer. This full solution covers the following key subjects: bar, ball, end, other, collision. This expansive textbook survival guide covers 26 chapters, and 2929 solutions.

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