A diving board 3.00 m long is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end (?Fig. E11.11?). The diving board is of uniform cross section and weighs 280 N. Find (a) the force at the support point and (b) the force at the left-hand end.

Solution 11E Step 1 : Introduction In this question, we have diving board and diver we need to find the force at the supporting point end of the board and at the left hand end of the board Data given Length of the diving board L = 3.0 m Support point L s 1.0 m Weight of the diver W =d500 N Weight of the board W =b280 N Considering the figure given From the figure we can notice that the this system is in equilibrium F=0 Hence force at point supporting point is given by F = M (d) + M (Lb/2) + P(L ) s Substituting values we get 0 = 500 N (3.0 m ) + 280 N (1.5 m) + P(1.0 m) P(1.0 m) = 1920 N Hence we have force at supporting point as 1920 N