Consider the following information on ultimate tensile strength (lb/in) for a sample of n = 4hard zirconium copper wire specimens (from “Characterization Methods for Fine Copper Wire,” ?Wire J. Intl., ?Aug., 1997: 74–80): Determine the values of the two middle sample observations (and don’t do it by successive guessing!).

Answer : Step 1 of 2 : Given, on ultimate tensile strength (lb/in) for a sample of n = 4 hard zirconium copper wire specimens x = 76,831, s = 140, smallest x = i6,683 and largest x = 7i,048. The claim is to find the values of the two middle sample observations Let, yi= x -ix = x -i76,831 Then , y = x - x 1 1 = 76683 - 76,831 = -148 And y =4x - x 4 = = 77048 - 76,831 = 217 Then, y = x - 76831 = 0 So, y 2 y = -3 y 1 + y 2 = -69 2 (xi x) Let, s = n 1 2 yi 180 = 3 y 2 = 3(180) 2 i = 97200