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As of April 2006, roughly 50 million .com web domain names

Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye ISBN: 9780321629111 32

Solution for problem 29E Chapter 2

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Probability and Statistics for Engineers and the Scientists | 9th Edition | ISBN: 9780321629111 | Authors: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 29E

As of April 2006, roughly 50 million .com web domain names were registered (e.g., yahoo.com). a. ?How many domain names consisting of just two letters in sequence can be formed? How many domain names of length two are there if digits as well as letters are permitted as characters? [?Note: ?A character length of three or more is now mandated.] b. ?How many domain names are there consisting of three letters in sequence? How many of this length are there if either letters or digits are permitted? [?Note: All are currently taken.] c.? nswer the questions posed in (b) for four-character sequences. d. ?As of April 2006, 97,786 of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected, what is the probability that it is already owned?

Step-by-Step Solution:

Answer : Step 1 of 4 : Given, As of April 2006, roughly 50 million .com web domain names were registered a) The claim is to find many domain names consisting of just two letters in sequence can be formed And How many domain names of length two are there if digits as well as letters are permitted as characters. There are 26 letters in alphabet. There are 26 possible ways to choose the first character and 26 possible ways to choose second Therefore, the possible number of domains with two letters is n n = 26 2 = 676 We have 10 digits and 26 alphabets So, totally 36 There are 36 possible ways to choose the first character as digits as well as letters and 36 possible ways to choose the second character as digits as well as letters. 2 therefore , n = 36 = 1296 Step 2 of 4 : b) The claim is to find many domain names consisting of three letters in sequence can be formed And How many of this length are there if either letters or digits are permitted There are 26 possible ways to choose the first character, 26 possible ways to choose second and 26 possible ways to choose third character. Therefore, the possible number of domains with three letters is n n = 26 3 = 17576 There are 36 possible ways to choose the first character as digits as well as letters, 36 possible ways to choose the second character as digits as well as letters and 36 possible ways to choose the third character as digits as well as letters. therefore , n = 363 = 46656

Step 3 of 4

Chapter 2, Problem 29E is Solved
Step 4 of 4

Textbook: Probability and Statistics for Engineers and the Scientists
Edition: 9
Author: Ronald E. Walpole; Raymond H. Myers; Sharon L. Myers; Keying E. Ye
ISBN: 9780321629111

This textbook survival guide was created for the textbook: Probability and Statistics for Engineers and the Scientists, edition: 9. Since the solution to 29E from 2 chapter was answered, more than 1752 students have viewed the full step-by-step answer. Probability and Statistics for Engineers and the Scientists was written by and is associated to the ISBN: 9780321629111. The full step-by-step solution to problem: 29E from chapter: 2 was answered by , our top Statistics solution expert on 05/06/17, 06:21PM. The answer to “As of April 2006, roughly 50 million .com web domain names were registered (e.g., yahoo.com). a. ?How many domain names consisting of just two letters in sequence can be formed? How many domain names of length two are there if digits as well as letters are permitted as characters? [?Note: ?A character length of three or more is now mandated.] b. ?How many domain names are there consisting of three letters in sequence? How many of this length are there if either letters or digits are permitted? [?Note: All are currently taken.] c.? nswer the questions posed in (b) for four-character sequences. d. ?As of April 2006, 97,786 of the four-character sequences using either letters or digits had not yet been claimed. If a four-character name is randomly selected, what is the probability that it is already owned?” is broken down into a number of easy to follow steps, and 138 words. This full solution covers the following key subjects: letters, Names, domain, character, digits. This expansive textbook survival guide covers 18 chapters, and 1582 solutions.

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