12-14. A car is to be hoisted by elevator to the fourth

Chapter 12, Problem 12-14

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QUESTION:

12-14. A car is to be hoisted by elevator to the fourth floor of a parking garage, which is 48 ft above the ground. If the elevator can accelerate at 0.6 ft/s2, decelerate at 0.3ft/s2, and reach a maximum speed of 8 ft/s, determine the shortest time to make the lift, starting from rest and ending at rest.

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QUESTION:

12-14. A car is to be hoisted by elevator to the fourth floor of a parking garage, which is 48 ft above the ground. If the elevator can accelerate at 0.6 ft/s2, decelerate at 0.3ft/s2, and reach a maximum speed of 8 ft/s, determine the shortest time to make the lift, starting from rest and ending at rest.

ANSWER:

Step 1 of 5

For constant acceleration, we can utilize the three following equations:

      (1)

  …  (2)

 …(3)

Where   is the final velocity,  is the initial velocity, is the constant acceleration ,  is the time,  and  are the initial and final displacement of a particle, respectively. Where  denotes the total distance travelled.

Step  2 of 5

Using equation (2), determine the maximum velocity of the elevator as it lifts up.

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