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The defect length of a corrosion defect in a pressurized
Chapter 5, Problem 39E(choose chapter or problem)
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard deviation 7.8 mm [suggested in the article ?"Reliability Evaluation of Corroding Pipelines Considering Multiple Failure Modes and Time-Dependent Internal Pressure" („I. of Infrastructure Systems, 2011: 216-224)]. a. What is the probability that defect length is at most 20 mm? Less than 20 mm? b. What is the 75th percentile of the defect length distribution—that is, the value that separates the smallest 75% of all lengths from the largest 25%? c. What is the 15th percentile of the defect length distribution? d. What values separate the middle 80% of the defect length distribution from the smallest 10% and the largest 10%?
Questions & Answers
QUESTION:
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard deviation 7.8 mm [suggested in the article ?"Reliability Evaluation of Corroding Pipelines Considering Multiple Failure Modes and Time-Dependent Internal Pressure" („I. of Infrastructure Systems, 2011: 216-224)]. a. What is the probability that defect length is at most 20 mm? Less than 20 mm? b. What is the 75th percentile of the defect length distribution—that is, the value that separates the smallest 75% of all lengths from the largest 25%? c. What is the 15th percentile of the defect length distribution? d. What values separate the middle 80% of the defect length distribution from the smallest 10% and the largest 10%?
ANSWER:Answer : Step 1: From the given information the defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 30 mm and standard deviation 7.8 mm. Normal Distribution Mean = 30 Standard Deviation ( sd ) = 7.8 Normal Distribution ~ N(0,1) The formula is given by, x Z = a). Now we have to find the probability that defect length is at most 20 mm. Less than 20 mm. Here x=20. x P(X < x) = ( ) P(X < 20) = ( 2030) 7.8 P(X < 20) = ( 10) 7.8 P(X < 20) = 1.2821 P(X < 20) =P ( Z < -1.2821) Then from the Standard Normal Table is P(X < 20) = 0.0999 Therefore the probability of less than 20 mm is 0.0999.