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# The article “Monte Carlo Simulation—Tool for Better ISBN: 9780321629111 32

## Solution for problem 40E Chapter 4

Probability and Statistics for Engineers and the Scientists | 9th Edition

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Problem 40E

The article “Monte Carlo Simulation—Tool for Better Understanding of LRFD” (?J. of Structural Engr., ?1993: 1586–1599) suggests that yield strength (ksi) for A36 grade steel is normally distributed with ? = 43 and ? = 4.5. a.? ?What is the probability that yield strength is at most 40? Greater than 60? b.? ?What yield strength value separates the strongest 75% from the others?

Step-by-Step Solution:

Answer Step 1 of 3 Given = 43 and = 4.5 a) The probability that yield strength is at most 40 Z=(x-)/ =(40-43)/4.5 =-0.67 P(x40)=P(z-0.67) =0.2514 The probability that yield strength is at most 40 is 0.2514 Step 2 of 3 The probability that yield strength is Greater than 60 Z=(x-)/ =(60-43)/4.5 =3.78 P(x60)=P(z3.78) =0 The probability that yield strength is Greater than 60 is 0

Step 3 of 3

##### ISBN: 9780321629111

This textbook survival guide was created for the textbook: Probability and Statistics for Engineers and the Scientists, edition: 9. The full step-by-step solution to problem: 40E from chapter: 4 was answered by , our top Statistics solution expert on 05/06/17, 06:21PM. Probability and Statistics for Engineers and the Scientists was written by and is associated to the ISBN: 9780321629111. The answer to “The article “Monte Carlo Simulation—Tool for Better Understanding of LRFD” (?J. of Structural Engr., ?1993: 1586–1599) suggests that yield strength (ksi) for A36 grade steel is normally distributed with ? = 43 and ? = 4.5. a.? ?What is the probability that yield strength is at most 40? Greater than 60? b.? ?What yield strength value separates the strongest 75% from the others?” is broken down into a number of easy to follow steps, and 63 words. This full solution covers the following key subjects: Yield, Strength, others, distributed, ENGR. This expansive textbook survival guide covers 18 chapters, and 1582 solutions. Since the solution to 40E from 4 chapter was answered, more than 341 students have viewed the full step-by-step answer.

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