Write Lewis structures for the following molecular formulas.
(a) N 2
(b) HCN
(c) HONO
(d) CO 2
(e) CH 3 CHNH
(f) HCO 2 H
(g) C 2 H 3 Cl
(h) HNNH
(i) C 3 H 6(one double bond)
(j) C3H4 (two double bonds)
(k) C3H4 (one triple bond)
Here we have to draw the Lewis structure of the following molecules.
Step-1
(a) N 2
The atomic number of N is 7. The electronic configuration is, 7N 1s2 2s2 2p3
The total number of valence electrons in N2 is = 5(2) = 10
The Lewis structure is,
Step-2
(b) HCN
In HCN, the central atom is C, surrounded by one N and one H atom.
1H 1s1 6C 1s2 2s2 2p2 7N 1s2 2s2 2p3
The total number of valence electrons = 1 + 4 + 5= 10
The Lewis structure is,
Step-3
(c) HONO
1H 1s1 8O 1s2 2s2 2p4 7N 1s2 2s2 2p3
Total number of valence electrons = 1 + 6(2) + 5 = 18
The Lewis structure is,
Step-4
(d) CO 2
In CO2 , the central atom is C , surrounded by two O atoms.
6C 1s2 2s2 2p2 8O 1s2 2s2 2p4
Total valence electrons in CO2 = 4 + 6 (2)= 12
The Lewis structure of CO2 is,
Step-5
(e) CH3CHNH
6C 1s2 2s2 2p2 1H 1s1 7N 1s2 2s2 2p3
Total number of valence electrons in CH3CHNH molecule is =2(4)+1(5)+1(5)=18e
The Lewis structure for CH3CHNH is
Step-6
(f) HCO2 H
The electronic configuration of H, C and O are,
1H 1s1 6C 1s2 2s2 2p2 8O 1s2 2s2 2p4
The total number of valence electrons = 1(2) + 4 + 6(2) = 18
The Lewis structure for HCO2 H is
Step-7
(g)...
