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Circle any lone pairs (pairs of nonbonding electrons) in

Organic Chemistry | 8th Edition | ISBN: 9780321768414 | Authors: L.G. Wade Jr ISBN: 9780321768414 33

Solution for problem 4P Chapter 1

Organic Chemistry | 8th Edition

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Organic Chemistry | 8th Edition | ISBN: 9780321768414 | Authors: L.G. Wade Jr

Organic Chemistry | 8th Edition

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Problem 4P

Circle any lone pairs (pairs of nonbonding electrons) in the structures you drew for Problem 1-3.

P1-3- Write Lewis structures for the following molecular formulas.

(a) N 2

(b) HCN

(c) HONO

(d) CO 2

(e) CH 3 CHNH

(f) HCO 2 H

(g) C 2 H 3 Cl

(h) HNNH

(i) C 3 H 6(one double bond)

(j) C3H4 (two double bonds)

(k) C3H4 (one triple bond)

Step-by-Step Solution:

Solution 4P:

Here, we are going to draw the Lewis structure of each molecule and based on it, we will circle the lone pairs of electrons.

((a) N2

Step 1:

Valence electron on N atom = 5

Total valence electrons in N2 molecule is = 5+ 5 =10 e

The Lewis structure for N2 molecule is

Step 2:

The number of lone pairs of electrons are marked by circle.

Here, in N2 molecule, No. of lone pair of electrons = 2

(b) HCN

Step 1:

Valence electron on N atom = 5

Valence electron on C atom = 4

Valence electron on H atom = 1

Total valence electrons in HCN molecule is = 5+ 4+1 =10 e

The Lewis structure for HCN molecule is

Step 2:

The number of lone pairs of electrons are marked by circle.

Here, in HCN  molecule, No. of lone pair of electrons = 1

(c) HONO

Step 1:

Valence electron on N atom = 5

Valence electron on O atom = 6

Valence electron on H atom = 1

Total valence electrons in HONO molecule is = 6 x2+ 5+1 =18 e

The Lewis structure for HONO molecule is

Step 2:

The number of lone pairs of electrons are marked by circle.

Here, in HONO  molecule, No. of lone pair of electrons = 5

(d) CO2

Step 1:

Valence electron on C atom = 4

Valence electron on O atom = 6

Total valence electrons in CO2 molecule is = 6 x2+4 =16 e

The Lewis structure for CO2 molecule is

Step 2:

The number of lone pairs of electrons are marked by circle.

Here, in CO2  molecule, No. of lone pair of electrons = 4

(e) CH 3CHNH

Step 1:

Valence electron on C atom = 4

Valence electron on N atom = 5

Total valence electrons in CH3CHNH molecule is =2x4+5+5=18e

The Lewis structure for CH3CHNH molecule is

Step 2:

The number of lone pairs of electrons are marked by circle.

Here, in  CH3CHNH  molecule, No. of lone pair of electrons = 1

(f)...

Step 2 of 3

Chapter 1, Problem 4P is Solved
Step 3 of 3

Textbook: Organic Chemistry
Edition: 8
Author: L.G. Wade Jr
ISBN: 9780321768414

Since the solution to 4P from 1 chapter was answered, more than 1210 students have viewed the full step-by-step answer. Organic Chemistry was written by and is associated to the ISBN: 9780321768414. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 8. This full solution covers the following key subjects: Bond, structures, pairs, Double, hco. This expansive textbook survival guide covers 25 chapters, and 1336 solutions. The full step-by-step solution to problem: 4P from chapter: 1 was answered by , our top Chemistry solution expert on 05/06/17, 06:41PM. The answer to “Circle any lone pairs (pairs of nonbonding electrons) in the structures you drew for 1-3.P1-3- Write Lewis structures for the following molecular formulas.(a) N 2(b) HCN(c) HONO(d) CO 2(e) CH 3 CHNH(f) HCO 2 H(g) C 2 H 3 Cl(h) HNNH(i) C 3 H 6(one double bond)(j) C3H4 (two double bonds)(k) C3H4 (one triple bond)” is broken down into a number of easy to follow steps, and 55 words.

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