Compute the empirical and molecular formulas for each of the following elemental analyses. In each case, propose at least one structure that fits the molecular formula.
C 
H 
N 
C1 
MW 

(a) 
40.0% 
6.67% 
0 
0 
90 
(b) 
32.0% 
6.67% 
18.7% 
0 
75 
(c) 
25.6% 
4.32% 
15.0% 
37.9% 
93 
(d) 
38.4% 
4.80% 
0 
56.8% 
125 
Solution 12P
(a) For the unknown compound, we do the following computations
The first computation divides the number of grams of carbon by 12, the number of grams of hydrogen by 1, and the number of grams of oxygen by 16. We compare these numbers by dividing then by the smallest number, 3.33. The final result is ratio of one carbon to two hydrogens to oxygen. This result gives the empirical formula or . The given molecular weight is 90, so our unknown compound must contain thrice this may atoms. The molecular formula must be 3() =
(b) For unknown compound, we do the following computations:
This result given the empirical formula .
The weight of one unit...