Solution Found!
Draw a Lewis structure for each species.(a) N 2 H 4(b) N 2
Chapter 1, Problem 25SP(choose chapter or problem)
Draw a Lewis structure for each species.
(a) \(\mathrm{N}_{2} \mathrm{H}_{4}\)
(b) \(\mathrm{N}_{2} \mathrm{H}_{2}\)
(c) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}_{2} \mathrm{Cl}\)
(d) \(\mathrm{CH}_{3} \mathrm{CN}\)
(e) \(\mathrm{CH}_{3} \mathrm{CHO}\)
(f) \(\mathrm{CH}_3\mathrm{S}(\mathrm{O})\mathrm{CH}_3\)
(g) \(\mathrm{H}_{2} \mathrm{SO}_{4}\)
(h) \(\mathrm{CH}_{3} \mathrm{NCO}\)
(i) \(\mathrm{CH}_{3} \mathrm{OSO}_{2} \mathrm{OCH}_{3}\)
(j) \(\mathrm{CH}_{3} \mathrm{C}(\mathrm{NH}) \mathrm{CH}_{3}\)
(k) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CNO}\)
Questions & Answers
QUESTION:
Draw a Lewis structure for each species.
(a) \(\mathrm{N}_{2} \mathrm{H}_{4}\)
(b) \(\mathrm{N}_{2} \mathrm{H}_{2}\)
(c) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}_{2} \mathrm{Cl}\)
(d) \(\mathrm{CH}_{3} \mathrm{CN}\)
(e) \(\mathrm{CH}_{3} \mathrm{CHO}\)
(f) \(\mathrm{CH}_3\mathrm{S}(\mathrm{O})\mathrm{CH}_3\)
(g) \(\mathrm{H}_{2} \mathrm{SO}_{4}\)
(h) \(\mathrm{CH}_{3} \mathrm{NCO}\)
(i) \(\mathrm{CH}_{3} \mathrm{OSO}_{2} \mathrm{OCH}_{3}\)
(j) \(\mathrm{CH}_{3} \mathrm{C}(\mathrm{NH}) \mathrm{CH}_{3}\)
(k) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CNO}\)
ANSWER:Step 1 of 26
Lewis formulas are written based on the number of electrons in the outermost energy level of the atoms involved. When atoms form covalent bonds, they will share enough electrons so that each atom forms covalent bonds, they will share enough electrons so that each atom will have eight electrons in its outer energy level.