Draw a Lewis structure for each species.

(a) N 2 H 4

(b) N 2 H 2

(c) (CH 3 ) 2 NH 2 Cl

(d) CH 3 CN

(e) CH3CHO

(f) CH3S(O)CH3

(g) H 2 SO 4

(h) CH 3 NCO

(i) CH 3 OSO 2 OCH 3

(j) CH 3 C(NH)CH 3

(k) (CH 3 ) 3 CNO

Solution 25SP

Step 1 </p>

Lewis formulas are written based on the number of electrons in the outermost energy level of the atoms involved. When atoms form covalent bond, they will share enough electrons so that each atom forms covalent bonds, they will share enough electrons so that each atom will have eight electrons in its outer energy level.

Step 2 </p>

(a) :

First draw the skeletal structure as follows:

The total number of valence electrons is calculated as follows:

Step 3 </p>

So, there are 14 valence electrons.

Step 4 </p>

Subtract 10 electrons to account for the bonds in the skeletal structure by leaving 4 electrons to distribute. Thus, 4 electrons are distributed as lone pairs on the two nitrogen atoms.

Therefore, the Lewis structure for is shown as follows:

Step 5 </p>

(b) :

First draw the skeletal structure as follows:

The total number of valence electrons is calculated as follows:

Step 6 </p>

So, there are 12 valence electrons.

Step 7 of 26</p>

Subtract 8 electrons to account for the bonds in the skeletal structure by leaving 4 electrons to distribute. Thus, 4 electrons are distributed as lone pairs on the two nitrogen atoms and a double bond is formed between the two nitrogen atoms.

Therefore, the Lewis structure for is shown as follows:

Step 8 </p>

(c) :

First draw the skeletal structure as follows:

The total number of valence electrons is calculated as follows:

So, there are 28 valence electrons.

Subtract 20 electrons to account for the bonds in the skeletal structure by leaving 8 electrons to distribute. Thus, 8 electrons are distributed as lone pairs on the chlorine atom. So, the Lewis structure is shown as follows: