Draw Lewis structures for(a) two compounds of formula

Organic Chemistry | 8th Edition | ISBN: 9780321768414 | Authors: L. G. Wade Jr

Problem 28SP Chapter 1

Organic Chemistry | 8th Edition

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Organic Chemistry | 8th Edition | ISBN: 9780321768414 | Authors: L. G. Wade Jr

Organic Chemistry | 8th Edition

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Problem 28SP

Draw Lewis structures for

(a) two compounds of formula C4H10

(b) two compounds of formulaC2H6O

(c) two compounds of formula C2H7N

(d) three compounds of formula C2H7NO

(e) three compounds of formula C3H8O2

(f) three compounds of formula C2H4O

Step-by-Step Solution:
Step 1 of 3

Solution 28SP

(a)

Count the number of valence electrons in the molecular formula  as follows:

Total valence electrons = 4(4) + 10(1)

                           = 16 + 10

                           = 26

So, there are 26 valence electrons.

Now draw one of the skeletal structures of the molecular formula  as follows:

Here, the number of electrons in this structure is 26.

Similarly, draw another possible structure with the molecular formula  as follows:

Here, the number of electrons in this structure is 26.

Therefore, the two compounds with the molecular formula  as follows:

(b)

Count the number of valence electrons in the molecular formula  as follows:

Total valence electrons = 2(4) + 6(1) + 1(6)

                        = 8 + 6 + 6

                        = 20        

So, there are 20 valence electrons.

Now draw one of the skeletal structures of the molecular formula  as follows:

Here, the number of valence electrons is 16. So, place the remaining 4 valence electrons as two lone pairs on oxygen atom.

Thus, the Lewis structure with the molecular formula  is as follows:

Similarly, draw another possible structure with the molecular formula  as follows:

Here, the number of valence electrons is 16. So, place the remaining 4 valence electrons as two lone pairs on oxygen atom.

Thus, the Lewis structure with the molecular formula  is as follows:

(c)

Count the number of valence electrons in the molecular formula  as follows:

Total valence electrons = 2(4)+7(1) + 1(5)

                         =8+7+5

                         =20

So, there are 20 valence electrons.

Now draw one of the skeletal structures of the molecular formula  as follows:

Here, the number of valence electrons is 18. So, place the remaining 2 valence electrons as one lone pair on nitrogen atom.

Thus, the Lewis structure with the molecular formula  is as follows:

Similarly, draw another possible structure with the molecular formula

Step 2 of 3

Chapter 1, Problem 28SP is Solved
Step 3 of 3

Textbook: Organic Chemistry
Edition: 8
Author: L. G. Wade Jr
ISBN: 9780321768414

Since the solution to 28SP from 1 chapter was answered, more than 1504 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Organic Chemistry, edition: 8. Organic Chemistry was written by and is associated to the ISBN: 9780321768414. The answer to “Draw Lewis structures for(a) two compounds of formula C4H10(b) two compounds of formulaC2H6O(c) two compounds of formula C2H7N(d) three compounds of formula C2H7NO(e) three compounds of formula C3H8O2(f) three compounds of formula C2H4O” is broken down into a number of easy to follow steps, and 33 words. This full solution covers the following key subjects: compounds, formula, formulac, draw, lewis. This expansive textbook survival guide covers 25 chapters, and 1336 solutions. The full step-by-step solution to problem: 28SP from chapter: 1 was answered by , our top Chemistry solution expert on 05/06/17, 06:41PM.

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