Show how you would synthesize the following alcohols from appropriate alkenes.
Step 1 </p>
(a) Oxymercuration-demercuration of 1-pentene gives Markovnikov product, 2-pentanol. Here the electrophile, , remains bonded to the less substituted end of the double bond. Reduction of the organomercurial alcohol gives the Markovnikov alcohol: 2-pentanol.
Step 2 </p>
(b) Hydroboration-oxidation of 1-methylcyclohex-1-ene gives anti-Markovnikov product, 2-methylcyclohexanol. Here, the hydroxyl group bonded to the less substituted end of the double bond and hydrogen is bonded to more substituted end of the double bond.