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# Perform each conversion.(a) 25 kWh to joules(b) 249 cal to ## Problem 53P Chapter 3

Introductory Chemistry | 5th Edition

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Problem 53P

Perform each conversion.

(a) 25 kWh to joules

(b) 249 cal to Calories

(c) 113 cal to kilowatt-hours

(d) 44 kJ to calories

Step-by-Step Solution:
Step 1 of 3

Solution 53P

Here, we have to perform the unit conversion.

(a) 25 kWh to joules

We know,

kilowatt = kilowatt-hour / hour

P = E / t watt = joule / second W = J / s Again,

1 kWh = 1000 W x (60 x 60 )s

= 36 x 105 Ws = 36 x 105 J

Thus,

25 kWh  x (36 x 105 J/ 1 kWh) = 900 x 105 J

Therefore 25 kWh = 900 x 105 J = 9 x 107 J

(b) 249 cal to Calories

We know,

1 Cal = 4.184 Joule

Therefore, the conversion factor = Thus,

249 cal x = 1041.82 Joule

Therefore,

249 cal = 1041.82 Joule = 1.041 kJ

(c) 113 cal to kilowatt-hours

We know,

1 cal = 4.184 watt-s

1000 watt = 1 kW

The conversion factors, , , ,...

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

The full step-by-step solution to problem: 53P from chapter: 3 was answered by Patricia, our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: CAl, Calories, Joules, conversion, kilowatt. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. Introductory Chemistry was written by Patricia and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The answer to “Perform each conversion.(a) 25 kWh to joules(b) 249 cal to Calories(c) 113 cal to kilowatt-hours(d) 44 kJ to calories” is broken down into a number of easy to follow steps, and 19 words. Since the solution to 53P from 3 chapter was answered, more than 335 students have viewed the full step-by-step answer.

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