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Complete the table:JcalCalkWh225 J ___5.38 X 10-2

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 55P Chapter 3

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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2
Problem 55P

Complete the table:

J

cal

Cal

kWh

225 J

 ___

5.38 X 10-2 Cal

___

___

8,21 x 105

___

___

___

___

___

295 kWh

___

___

155 Cal

___

Step-by-Step Solution:

Solution 55P

Step 1:

Conversion of units can be done by a method called unit factor method based on the relationship between different units that expresses the same quantity.

Step 2:

The relation between J-cal, cal-Cal and Cal-kWh are given below:

1 J = 0.2389 cal

1 cal = 0.001 Cal

1 Cal = 0.00116 kWh

1 cal = 4.184 J

1 kWh = 860.05 Cal

1Cal = 1000 cal

Step 3 of 3

Chapter 3, Problem 55P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Complete the table:JcalCalkWh225 J ___5.38 X 10-2

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