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Complete the table:JcalCalkWh7.88 x 106 J1.88 x 106

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 56P Chapter 3

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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2
Problem 56P

Complete the table:

J

cal

Cal

kWh

7.88 x 106 J

1.88 x 106 cal

___

___

___

___

1154 Cal

___

___

88.4 cal

___

___

___

___

___

125 kWh

Step-by-Step Solution:
Step 1 of 3

Problem 56P

Complete the table:

J

cal

Cal

kWh

7.88 x 106 J

1.88 x 106 cal

___

___

___

___

1154 Cal

___

___

88.4 cal

___

___

___

___

___

125 kWh

Solution: Here, we are going to complete the table given in the problem.

Step1:

Conversion of units can be done by a method called unit factor method based on the relationship between different units that expresses the same quantity.

Step2:

The relation between J-cal, cal-Cal and Cal-kWh are given below:

1...

Step 2 of 3

Chapter 3, Problem 56P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: CAl, kwh, complete, Table. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “Complete the table:JcalCalkWh7.88 x 106 J1.88 x 106 cal____________1154 Cal______88.4 cal_______________125 kWh” is broken down into a number of easy to follow steps, and 12 words. The full step-by-step solution to problem: 56P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 56P from 3 chapter was answered, more than 535 students have viewed the full step-by-step answer.

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Complete the table:JcalCalkWh7.88 x 106 J1.88 x 106

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