Calculate the temperature change that occurs when 248 cal of heat are added to 24 g of water.

Solution 83P :

Step 1:

Here, we have to Calculate the change in temperature that occurs when 248 cal of heat are added to 24 g of water.

Amount of heat = 248 cal

Amount of water = 24 g

Let’s convert the heat in calories to J :

1 cal = 4.184 kJ

Therefore, 248 cal in kJ is :

= 248 cal

= 1037.632 J

The specific heat of water is 4.186 j/g °C

Now, let’s calculate the change in temperature () :

Q(Amount of heat) = m (mass) C(Specific heat) (Temperature change)

...