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Calculate the temperature change that occurs when 248 cal

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 83P Chapter 3

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 83P

Calculate the temperature change that occurs when 248 cal of heat are added to 24 g of water.

Step-by-Step Solution:

Solution 83P :

Step 1:

Here, we have to Calculate the change in temperature that occurs when 248 cal of heat are added to 24 g of water.

Amount of heat = 248 cal

Amount of water = 24 g

Let’s convert the heat in calories to J :

1 cal = 4.184 kJ

Therefore, 248 cal in kJ is :

= 248 cal

                = 1037.632 J

The specific heat of water is 4.186 j/g °C

Now, let’s calculate the change in temperature () :

  Q(Amount of heat) = m (mass) C(Specific heat)   (Temperature change)

         ...

Step 2 of 3

Chapter 3, Problem 83P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The full step-by-step solution to problem: 83P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 83P from 3 chapter was answered, more than 1958 students have viewed the full step-by-step answer. This full solution covers the following key subjects: added, CAl, calculate, change, heat. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “Calculate the temperature change that occurs when 248 cal of heat are added to 24 g of water.” is broken down into a number of easy to follow steps, and 18 words.

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