Calculate the temperature change that occurs when 248 cal of heat are added to 24 g of water.
Solution 83P :
Here, we have to Calculate the change in temperature that occurs when 248 cal of heat are added to 24 g of water.
Amount of heat = 248 cal
Amount of water = 24 g
Let’s convert the heat in calories to J :
1 cal = 4.184 kJ
Therefore, 248 cal in kJ is :
= 248 cal
= 1037.632 J
The specific heat of water is 4.186 j/g °C
Now, let’s calculate the change in temperature () :
Q(Amount of heat) = m (mass) C(Specific heat) (Temperature change)
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
The full step-by-step solution to problem: 83P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 83P from 3 chapter was answered, more than 1958 students have viewed the full step-by-step answer. This full solution covers the following key subjects: added, CAl, calculate, change, heat. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “Calculate the temperature change that occurs when 248 cal of heat are added to 24 g of water.” is broken down into a number of easy to follow steps, and 18 words.