Calculate the final temperature of 32 mL of ethanol initially at 11 °C upon absorption of 562 J of heat, (density of ethanol = 0.789 g/mL)

Solution 94P

Here, we are going to calculate the final temperature of 32 mL of ethanol initially at 11oC upon absorption of 562 J of heat.

Step 1:

Specific heat is the amount of heat required per unit mass to raise the temperature by one degree celsius. If ‘C’ be the specific heat, ‘m’ be the mass, ‘Q’ be the heat absorbed and ΔT be the change in temperature, then,

Q = m x C x ΔT -----(1)

where ΔT = final temperature(T2) - initial temperature(T1)

Step 2:

Given, density of ethanol = 0.789 g/mL

Volume of ethanol = 32 mL

Using the relation density = mass/volume, we get,

Mass of ethanol = density x volume

= 0.789 g/mL x 32 mL

= 25.248 g