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A pure gold ring with a volume of 1.57 cm3 is initially at 11.4 °C. When it is put on

Chapter 3, Problem 95P

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QUESTION:

A pure gold ring with a volume of \(1.57\mathrm{\ cm}^3\) is initially at \(11.4\ ^{\circ}\mathrm{C}\). When it is put on, it warms to \(29.5\ ^{\circ}\mathrm{C}\). How much heat does the ring absorb? (density of gold = \(19.3\mathrm{\ g}/\mathrm{cm}^3\)).

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QUESTION:

A pure gold ring with a volume of \(1.57\mathrm{\ cm}^3\) is initially at \(11.4\ ^{\circ}\mathrm{C}\). When it is put on, it warms to \(29.5\ ^{\circ}\mathrm{C}\). How much heat does the ring absorb? (density of gold = \(19.3\mathrm{\ g}/\mathrm{cm}^3\)).

ANSWER:

Step 1 of 2

The amount of heat required can be calculated using the equation given below:

\(q=m c \Delta T\)

where,

\(\begin{array}{l} \mathrm{q}=\text { heat energy } \\ \mathrm{m}=\text { mass } \\ \mathrm{c}=\text { specific heat } \\ \Delta \mathrm{T}=\text { change in temperature } \end{array}\)

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