Solution Found!
A pure gold ring with a volume of 1.57 cm3 is initially at 11.4 °C. When it is put on
Chapter 3, Problem 95P(choose chapter or problem)
A pure gold ring with a volume of \(1.57\mathrm{\ cm}^3\) is initially at \(11.4\ ^{\circ}\mathrm{C}\). When it is put on, it warms to \(29.5\ ^{\circ}\mathrm{C}\). How much heat does the ring absorb? (density of gold = \(19.3\mathrm{\ g}/\mathrm{cm}^3\)).
Questions & Answers
QUESTION:
A pure gold ring with a volume of \(1.57\mathrm{\ cm}^3\) is initially at \(11.4\ ^{\circ}\mathrm{C}\). When it is put on, it warms to \(29.5\ ^{\circ}\mathrm{C}\). How much heat does the ring absorb? (density of gold = \(19.3\mathrm{\ g}/\mathrm{cm}^3\)).
ANSWER:Step 1 of 2
The amount of heat required can be calculated using the equation given below:
\(q=m c \Delta T\)
where,
\(\begin{array}{l} \mathrm{q}=\text { heat energy } \\ \mathrm{m}=\text { mass } \\ \mathrm{c}=\text { specific heat } \\ \Delta \mathrm{T}=\text { change in temperature } \end{array}\)