How much heat in kilojoules is required to heat 56 L of water from 85 °F to 212 °F?

Solution 97P

Step 1:

The amount of heat required can be calculated using the equation given below

q = mcΔT

where

q = heat energy

m = mass

c = specific heat

ΔT = change in temperature

Step 2:

ΔT is to be found.

Temperature inF has to be converted to temperature in C

Tc=(Tf -32)5/9

Tf=85

Tc=(85-32)5/9=29C

Tf=212

Tc=(212-32)5/9=100C

ΔT=100-29=71C