What is the temperature change in Celsius when 29.5 L of water absorbs 2.3 kWh of heat?
Step 1 of 3
29.5 L of water has a mass of 29.5 kg
1 Watt-second = 1 joule
1 kW-second = 1000 joules
1 kW-hour = 1000*3600 joules = 3600 kJ
2.3 kW-hours = 2.3*3600 kJ = 8280 kJ
Heat gained by water = mass*specific heat*temperature rise
specific heat of water = 4.18 kJ/kgC
8280 = 29.5*4.18*temperature rise
temperature rise = 8280/(29.5*4.18) = 8280/123.31 = 67.147 degrees C
= 67.1 degrees C to 3 significant figures.
Textbook: Introductory Chemistry
Author: Nivaldo J Tro
Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The answer to “What is the temperature change in Celsius when 29.5 L of water absorbs 2.3 kWh of heat?” is broken down into a number of easy to follow steps, and 17 words. The full step-by-step solution to problem: 99P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 99P from 3 chapter was answered, more than 977 students have viewed the full step-by-step answer. This full solution covers the following key subjects: absorbs, celsius, change, heat, kwh. This expansive textbook survival guide covers 19 chapters, and 2046 solutions.